Base | Representation |
---|---|
bin | 110011111000000101… |
… | …0110010101100110110 |
3 | 101122112220102100220010 |
4 | 1213300022302230312 |
5 | 3311123301341400 |
6 | 123102244321050 |
7 | 11022453331401 |
oct | 1476012625466 |
9 | 348486370803 |
10 | 111403543350 |
11 | 43278439aa0 |
12 | 197109a3186 |
13 | a675219428 |
14 | 556b778d38 |
15 | 2d7043c450 |
hex | 19f02b2b36 |
111403543350 has 192 divisors, whose sum is σ = 308779879680. Its totient is φ = 26352230400.
The previous prime is 111403543333. The next prime is 111403543373. The reversal of 111403543350 is 53345304111.
111403543350 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 13332774 + ... + 13341126.
It is an arithmetic number, because the mean of its divisors is an integer number (1608228540).
Almost surely, 2111403543350 is an apocalyptic number.
111403543350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 111403543350, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (154389939840).
111403543350 is an abundant number, since it is smaller than the sum of its proper divisors (197376336330).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111403543350 is a wasteful number, since it uses less digits than its factorization.
111403543350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8575 (or 8570 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 111403543350 its reverse (53345304111), we get a palindrome (164748847461).
The spelling of 111403543350 in words is "one hundred eleven billion, four hundred three million, five hundred forty-three thousand, three hundred fifty".
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