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11140497343 is a prime number
BaseRepresentation
bin10100110000000011…
…00111111110111111
31001202101210220100201
422120001213332333
5140303431403333
65041243304331
7543033444043
oct123001477677
931671726321
1011140497343
1147a757a5a8
1221aab1b0a7
13108707a181
14779804023
1545309317d
hex298067fbf

11140497343 has 2 divisors, whose sum is σ = 11140497344. Its totient is φ = 11140497342.

The previous prime is 11140497257. The next prime is 11140497397. The reversal of 11140497343 is 34379404111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11140497343 is a prime.

It is a super-2 number, since 2×111404973432 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11140447343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570248671 + 5570248672.

It is an arithmetic number, because the mean of its divisors is an integer number (5570248672).

Almost surely, 211140497343 is an apocalyptic number.

11140497343 is a deficient number, since it is larger than the sum of its proper divisors (1).

11140497343 is an equidigital number, since it uses as much as digits as its factorization.

11140497343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36288, while the sum is 37.

The spelling of 11140497343 in words is "eleven billion, one hundred forty million, four hundred ninety-seven thousand, three hundred forty-three".