1114050013 has 2 divisors, whose sum is σ = 1114050014. Its totient is φ = 1114050012.

The previous prime is 1114049953. The next prime is 1114050023. The reversal of 1114050013 is 3100504111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1098392164 + 15657849 = 33142^2 + 3957^2 .

It is an emirp because it is prime and its reverse (3100504111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1114050013 - 2²¹ = 1111952861 is a prime.

It is a super-2 number, since 2×1114050013² = 2482214862930600338, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1114050023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557025006 + 557025007.

It is an arithmetic number, because the mean of its divisors is an integer number (557025007).

Almost surely, 2^1114050013 is an apocalyptic number.

It is an amenable number.

1114050013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114050013 is an equidigital number, since it uses as much as digits as its factorization.

1114050013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 1114050013 is about 33377.3877497925. The cubic root of 1114050013 is about 1036.6565498519.

Adding to 1114050013 its reverse (3100504111), we get a palindrome (4214554124).

The spelling of 1114050013 in words is "one billion, one hundred fourteen million, fifty thousand, thirteen".