Base | Representation |
---|---|
bin | 10000001101100011010… |
… | …100100010000110010101 |
3 | 10221111120221210220100101 |
4 | 100031203110202012111 |
5 | 121223100042402342 |
6 | 2211443213214101 |
7 | 143326342015315 |
oct | 20154324420625 |
9 | 3844527726311 |
10 | 1114062856597 |
11 | 39a520491329 |
12 | 15bab5491331 |
13 | 810954243b2 |
14 | 3bcc7063445 |
15 | 1dea539d3b7 |
hex | 10363522195 |
1114062856597 has 2 divisors, whose sum is σ = 1114062856598. Its totient is φ = 1114062856596.
The previous prime is 1114062856589. The next prime is 1114062856601. The reversal of 1114062856597 is 7956582604111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 835151065956 + 278911790641 = 913866^2 + 528121^2 .
It is a cyclic number.
It is not a de Polignac number, because 1114062856597 - 23 = 1114062856589 is a prime.
It is a super-2 number, since 2×11140628565972 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1114062856507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557031428298 + 557031428299.
It is an arithmetic number, because the mean of its divisors is an integer number (557031428299).
Almost surely, 21114062856597 is an apocalyptic number.
It is an amenable number.
1114062856597 is a deficient number, since it is larger than the sum of its proper divisors (1).
1114062856597 is an equidigital number, since it uses as much as digits as its factorization.
1114062856597 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3628800, while the sum is 55.
The spelling of 1114062856597 in words is "one trillion, one hundred fourteen billion, sixty-two million, eight hundred fifty-six thousand, five hundred ninety-seven".
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