Base | Representation |
---|---|
bin | 10100110000000100… |
… | …01110010001111001 |
3 | 1001202102002212112021 |
4 | 22120002032101321 |
5 | 140304001413301 |
6 | 5041250514441 |
7 | 543034666255 |
oct | 123002162171 |
9 | 31672085467 |
10 | 11140654201 |
11 | 47a7677436 |
12 | 21aab95a21 |
13 | 10871036a1 |
14 | 779845265 |
15 | 4530c48a1 |
hex | 29808e479 |
11140654201 has 2 divisors, whose sum is σ = 11140654202. Its totient is φ = 11140654200.
The previous prime is 11140654169. The next prime is 11140654229. The reversal of 11140654201 is 10245604111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10806642025 + 334012176 = 103955^2 + 18276^2 .
It is an emirp because it is prime and its reverse (10245604111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11140654201 - 25 = 11140654169 is a prime.
It is a super-2 number, since 2×111406542012 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11140654241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570327100 + 5570327101.
It is an arithmetic number, because the mean of its divisors is an integer number (5570327101).
Almost surely, 211140654201 is an apocalyptic number.
It is an amenable number.
11140654201 is a deficient number, since it is larger than the sum of its proper divisors (1).
11140654201 is an equidigital number, since it uses as much as digits as its factorization.
11140654201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 25.
The spelling of 11140654201 in words is "eleven billion, one hundred forty million, six hundred fifty-four thousand, two hundred one".
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