111410333124131 has 2 divisors, whose sum is σ = 111410333124132. Its totient is φ = 111410333124130.

The previous prime is 111410333124113. The next prime is 111410333124137. The reversal of 111410333124131 is 131421333014111.

It is a happy number.

Together with previous prime (111410333124113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111410333124131 - 2¹⁰ = 111410333123107 is a prime.

It is a super-2 number, since 2×111410333124131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111410333124094 and 111410333124103.

It is not a weakly prime, because it can be changed into another prime (111410333124137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55705166562065 + 55705166562066.

It is an arithmetic number, because the mean of its divisors is an integer number (55705166562066).

Almost surely, 2^{111410333124131} is an apocalyptic number.

111410333124131 is a deficient number, since it is larger than the sum of its proper divisors (1).

111410333124131 is an equidigital number, since it uses as much as digits as its factorization.

111410333124131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

Adding to 111410333124131 its reverse (131421333014111), we get a palindrome (242831666138242).

The spelling of 111410333124131 in words is "one hundred eleven trillion, four hundred ten billion, three hundred thirty-three million, one hundred twenty-four thousand, one hundred thirty-one".