Base | Representation |
---|---|
bin | 110011111000010010… |
… | …1000100110001110111 |
3 | 101122120101101101220122 |
4 | 1213300211010301313 |
5 | 3311132032330033 |
6 | 123103052122155 |
7 | 11022566025302 |
oct | 1476045046167 |
9 | 348511341818 |
10 | 111410433143 |
11 | 43281315439 |
12 | 1971316635b |
13 | a67678c429 |
14 | 556c64db39 |
15 | 2d70d4da98 |
hex | 19f0944c77 |
111410433143 has 2 divisors, whose sum is σ = 111410433144. Its totient is φ = 111410433142.
The previous prime is 111410433097. The next prime is 111410433149. The reversal of 111410433143 is 341334014111.
It is a strong prime.
It is an emirp because it is prime and its reverse (341334014111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111410433143 is a prime.
It is a super-2 number, since 2×1114104331432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111410433149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55705216571 + 55705216572.
It is an arithmetic number, because the mean of its divisors is an integer number (55705216572).
Almost surely, 2111410433143 is an apocalyptic number.
111410433143 is a deficient number, since it is larger than the sum of its proper divisors (1).
111410433143 is an equidigital number, since it uses as much as digits as its factorization.
111410433143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 111410433143 its reverse (341334014111), we get a palindrome (452744447254).
The spelling of 111410433143 in words is "one hundred eleven billion, four hundred ten million, four hundred thirty-three thousand, one hundred forty-three".
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