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11141314013 is a prime number
BaseRepresentation
bin10100110000001001…
…01111010111011101
31001202110100101121202
422120010233113131
5140304134022023
65041313005245
7543043415024
oct123004572735
931673311552
1011141314013
1147a7a88135
1221ab253825
1310872a4acb
147799778bb
154531a5128
hex29812f5dd

11141314013 has 2 divisors, whose sum is σ = 11141314014. Its totient is φ = 11141314012.

The previous prime is 11141313983. The next prime is 11141314039. The reversal of 11141314013 is 31041314111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10860349369 + 280964644 = 104213^2 + 16762^2 .

It is an emirp because it is prime and its reverse (31041314111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11141314013 - 26 = 11141313949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11141314043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570657006 + 5570657007.

It is an arithmetic number, because the mean of its divisors is an integer number (5570657007).

Almost surely, 211141314013 is an apocalyptic number.

It is an amenable number.

11141314013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11141314013 is an equidigital number, since it uses as much as digits as its factorization.

11141314013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 11141314013 its reverse (31041314111), we get a palindrome (42182628124).

The spelling of 11141314013 in words is "eleven billion, one hundred forty-one million, three hundred fourteen thousand, thirteen".