1114146550333 has 2 divisors, whose sum is σ = 1114146550334. Its totient is φ = 1114146550332.

The previous prime is 1114146550301. The next prime is 1114146550379. The reversal of 1114146550333 is 3330556414111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 820325095524 + 293821454809 = 905718^2 + 542053^2 .

It is a cyclic number.

It is not a de Polignac number, because 1114146550333 - 2⁵ = 1114146550301 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1114146550292 and 1114146550301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1114140550333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557073275166 + 557073275167.

It is an arithmetic number, because the mean of its divisors is an integer number (557073275167).

Almost surely, 2^{1114146550333} is an apocalyptic number.

It is an amenable number.

1114146550333 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114146550333 is an equidigital number, since it uses as much as digits as its factorization.

1114146550333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 37.

The spelling of 1114146550333 in words is "one trillion, one hundred fourteen billion, one hundred forty-six million, five hundred fifty thousand, three hundred thirty-three".