Base | Representation |
---|---|
bin | 10100110000001110… |
… | …11010001110011001 |
3 | 1001202111122221121121 |
4 | 22120013122032121 |
5 | 140304323420344 |
6 | 5041340005241 |
7 | 543052361251 |
oct | 123007321631 |
9 | 31674587547 |
10 | 11142013849 |
11 | 47a8415a0a |
12 | 21ab530821 |
13 | 108748b505 |
14 | 779aba961 |
15 | 453292684 |
hex | 2981da399 |
11142013849 has 2 divisors, whose sum is σ = 11142013850. Its totient is φ = 11142013848.
The previous prime is 11142013829. The next prime is 11142013853. The reversal of 11142013849 is 94831024111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9905225625 + 1236788224 = 99525^2 + 35168^2 .
It is an emirp because it is prime and its reverse (94831024111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11142013849 - 27 = 11142013721 is a prime.
It is a super-2 number, since 2×111420138492 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11142013829) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571006924 + 5571006925.
It is an arithmetic number, because the mean of its divisors is an integer number (5571006925).
Almost surely, 211142013849 is an apocalyptic number.
It is an amenable number.
11142013849 is a deficient number, since it is larger than the sum of its proper divisors (1).
11142013849 is an equidigital number, since it uses as much as digits as its factorization.
11142013849 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 34.
The spelling of 11142013849 in words is "eleven billion, one hundred forty-two million, thirteen thousand, eight hundred forty-nine".
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