Base | Representation |
---|---|
bin | 10000001101101100001… |
… | …101111110110010011001 |
3 | 10221111222100200222111121 |
4 | 100031230031332302121 |
5 | 121223401301242131 |
6 | 2211510104525241 |
7 | 143333133605446 |
oct | 20155415766231 |
9 | 3844870628447 |
10 | 1114212134041 |
11 | 39a59777a716 |
12 | 15bb37480821 |
13 | 810ba32c446 |
14 | 3bcdcc009cd |
15 | 1deb3538911 |
hex | 1036c37ec99 |
1114212134041 has 2 divisors, whose sum is σ = 1114212134042. Its totient is φ = 1114212134040.
The previous prime is 1114212134033. The next prime is 1114212134053. The reversal of 1114212134041 is 1404312124111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1064704104025 + 49508030016 = 1031845^2 + 222504^2 .
It is a cyclic number.
It is not a de Polignac number, because 1114212134041 - 23 = 1114212134033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1114212133997 and 1114212134015.
It is not a weakly prime, because it can be changed into another prime (1114212134011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557106067020 + 557106067021.
It is an arithmetic number, because the mean of its divisors is an integer number (557106067021).
Almost surely, 21114212134041 is an apocalyptic number.
It is an amenable number.
1114212134041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1114212134041 is an equidigital number, since it uses as much as digits as its factorization.
1114212134041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 1114212134041 its reverse (1404312124111), we get a palindrome (2518524258152).
The spelling of 1114212134041 in words is "one trillion, one hundred fourteen billion, two hundred twelve million, one hundred thirty-four thousand, forty-one".
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