Base | Representation |
---|---|
bin | 10100110000010001… |
… | …00011000010111001 |
3 | 1001202112020002202201 |
4 | 22120020203002321 |
5 | 140304412441441 |
6 | 5041350230201 |
7 | 543055042663 |
oct | 123010430271 |
9 | 31675202681 |
10 | 11142312121 |
11 | 47a85aa016 |
12 | 21ab655361 |
13 | 10875641c5 |
14 | 779b57533 |
15 | 453300c31 |
hex | 2982230b9 |
11142312121 has 2 divisors, whose sum is σ = 11142312122. Its totient is φ = 11142312120.
The previous prime is 11142312089. The next prime is 11142312131. The reversal of 11142312121 is 12121324111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10173546496 + 968765625 = 100864^2 + 31125^2 .
It is a cyclic number.
It is not a de Polignac number, because 11142312121 - 25 = 11142312089 is a prime.
It is a super-2 number, since 2×111423121212 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11142312131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571156060 + 5571156061.
It is an arithmetic number, because the mean of its divisors is an integer number (5571156061).
Almost surely, 211142312121 is an apocalyptic number.
It is an amenable number.
11142312121 is a deficient number, since it is larger than the sum of its proper divisors (1).
11142312121 is an equidigital number, since it uses as much as digits as its factorization.
11142312121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 96, while the sum is 19.
Adding to 11142312121 its reverse (12121324111), we get a palindrome (23263636232).
The spelling of 11142312121 in words is "eleven billion, one hundred forty-two million, three hundred twelve thousand, one hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •