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1114313333537 is a prime number
BaseRepresentation
bin10000001101110010010…
…000000001101100100001
310221112020102010110010002
4100031302100001230201
5121224103203133122
62211524121545345
7143335503024635
oct20156220015441
93845212113102
101114313333537
1139a639910368
1215bb65345255
13811052a2bc1
143bd0c424dc5
151debc378992
hex10372401b21

1114313333537 has 2 divisors, whose sum is σ = 1114313333538. Its totient is φ = 1114313333536.

The previous prime is 1114313333521. The next prime is 1114313333621. The reversal of 1114313333537 is 7353333134111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1107358440721 + 6954892816 = 1052311^2 + 83396^2 .

It is an emirp because it is prime and its reverse (7353333134111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1114313333537 - 24 = 1114313333521 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1114313333537.

It is not a weakly prime, because it can be changed into another prime (1114313336537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557156666768 + 557156666769.

It is an arithmetic number, because the mean of its divisors is an integer number (557156666769).

Almost surely, 21114313333537 is an apocalyptic number.

It is an amenable number.

1114313333537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114313333537 is an equidigital number, since it uses as much as digits as its factorization.

1114313333537 is an evil number, because the sum of its binary digits is even.

The product of its digits is 102060, while the sum is 38.

Adding to 1114313333537 its reverse (7353333134111), we get a palindrome (8467646467648).

The spelling of 1114313333537 in words is "one trillion, one hundred fourteen billion, three hundred thirteen million, three hundred thirty-three thousand, five hundred thirty-seven".