111432541120031 has 2 divisors, whose sum is σ = 111432541120032. Its totient is φ = 111432541120030.

The previous prime is 111432541119947. The next prime is 111432541120081. The reversal of 111432541120031 is 130021145234111.

It is a strong prime.

It is an emirp because it is prime and its reverse (130021145234111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111432541120031 is a prime.

It is a super-2 number, since 2×111432541120031² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111432541119976 and 111432541120003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111432541120081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55716270560015 + 55716270560016.

It is an arithmetic number, because the mean of its divisors is an integer number (55716270560016).

Almost surely, 2^{111432541120031} is an apocalyptic number.

111432541120031 is a deficient number, since it is larger than the sum of its proper divisors (1).

111432541120031 is an equidigital number, since it uses as much as digits as its factorization.

111432541120031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 29.

Adding to 111432541120031 its reverse (130021145234111), we get a palindrome (241453686354142).

The spelling of 111432541120031 in words is "one hundred eleven trillion, four hundred thirty-two billion, five hundred forty-one million, one hundred twenty thousand, thirty-one".