Base | Representation |
---|---|
bin | 10100110000011000… |
… | …10110110000000101 |
3 | 1001202121002211001211 |
4 | 22120030112300011 |
5 | 140310141412331 |
6 | 5041423451421 |
7 | 543066401152 |
oct | 123014266005 |
9 | 31677084054 |
10 | 11143310341 |
11 | 47a9120a99 |
12 | 21aba56b71 |
13 | 1087823677 |
14 | 779d37229 |
15 | 45344b8b1 |
hex | 298316c05 |
11143310341 has 2 divisors, whose sum is σ = 11143310342. Its totient is φ = 11143310340.
The previous prime is 11143310329. The next prime is 11143310357. The reversal of 11143310341 is 14301334111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9183388900 + 1959921441 = 95830^2 + 44271^2 .
It is a cyclic number.
It is not a de Polignac number, because 11143310341 - 215 = 11143277573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11143310141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571655170 + 5571655171.
It is an arithmetic number, because the mean of its divisors is an integer number (5571655171).
Almost surely, 211143310341 is an apocalyptic number.
It is an amenable number.
11143310341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11143310341 is an equidigital number, since it uses as much as digits as its factorization.
11143310341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 11143310341 its reverse (14301334111), we get a palindrome (25444644452).
The spelling of 11143310341 in words is "eleven billion, one hundred forty-three million, three hundred ten thousand, three hundred forty-one".
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