Base | Representation |
---|---|
bin | 1010001000101000000100… |
… | …0111010001010001011011 |
3 | 1110110021211112012200012221 |
4 | 2202022001013101101123 |
5 | 2430033000200114233 |
6 | 35411055550444511 |
7 | 2230035433334143 |
oct | 242120107212133 |
9 | 43407745180187 |
10 | 11143311332443 |
11 | 3606940818134 |
12 | 12bb794503737 |
13 | 62aa6b035554 |
14 | 2a74a688d923 |
15 | 144ce2e6b42d |
hex | a22811d145b |
11143311332443 has 2 divisors, whose sum is σ = 11143311332444. Its totient is φ = 11143311332442.
The previous prime is 11143311332411. The next prime is 11143311332507. The reversal of 11143311332443 is 34423311334111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11143311332443 - 25 = 11143311332411 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11143311332399 and 11143311332408.
It is not a weakly prime, because it can be changed into another prime (11143311332143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571655666221 + 5571655666222.
It is an arithmetic number, because the mean of its divisors is an integer number (5571655666222).
Almost surely, 211143311332443 is an apocalyptic number.
11143311332443 is a deficient number, since it is larger than the sum of its proper divisors (1).
11143311332443 is an equidigital number, since it uses as much as digits as its factorization.
11143311332443 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 31104, while the sum is 34.
Adding to 11143311332443 its reverse (34423311334111), we get a palindrome (45566622666554).
The spelling of 11143311332443 in words is "eleven trillion, one hundred forty-three billion, three hundred eleven million, three hundred thirty-two thousand, four hundred forty-three".
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