1114332017 has 2 divisors, whose sum is σ = 1114332018. Its totient is φ = 1114332016.

The previous prime is 1114332001. The next prime is 1114332029. The reversal of 1114332017 is 7102334111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1076889856 + 37442161 = 32816^2 + 6119^2 .

It is an emirp because it is prime and its reverse (7102334111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1114332017 - 2⁴ = 1114332001 is a prime.

It is a super-2 number, since 2×1114332017² = 2483471688222576578, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1114331983 and 1114332001.

It is not a weakly prime, because it can be changed into another prime (1114332067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557166008 + 557166009.

It is an arithmetic number, because the mean of its divisors is an integer number (557166009).

Almost surely, 2^1114332017 is an apocalyptic number.

It is an amenable number.

1114332017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114332017 is an equidigital number, since it uses as much as digits as its factorization.

1114332017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 23.

The square root of 1114332017 is about 33381.6119592808. The cubic root of 1114332017 is about 1036.7440134986.

Adding to 1114332017 its reverse (7102334111), we get a palindrome (8216666128).

The spelling of 1114332017 in words is "one billion, one hundred fourteen million, three hundred thirty-two thousand, seventeen".