Base | Representation |
---|---|
bin | 110011111000111111… |
… | …1011011100001001011 |
3 | 101122122000221210010121 |
4 | 1213301333123201023 |
5 | 3311204113303433 |
6 | 123105255524111 |
7 | 11023304246056 |
oct | 1476177334113 |
9 | 348560853117 |
10 | 111434119243 |
11 | 43293723127 |
12 | 1971b089637 |
13 | a67b663585 |
14 | 5571857a9d |
15 | 2d72e7bc2d |
hex | 19f1fdb84b |
111434119243 has 2 divisors, whose sum is σ = 111434119244. Its totient is φ = 111434119242.
The previous prime is 111434119219. The next prime is 111434119271. The reversal of 111434119243 is 342911434111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111434119243 - 225 = 111400564811 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111434119199 and 111434119208.
It is not a weakly prime, because it can be changed into another prime (111434119343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55717059621 + 55717059622.
It is an arithmetic number, because the mean of its divisors is an integer number (55717059622).
Almost surely, 2111434119243 is an apocalyptic number.
111434119243 is a deficient number, since it is larger than the sum of its proper divisors (1).
111434119243 is an equidigital number, since it uses as much as digits as its factorization.
111434119243 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10368, while the sum is 34.
The spelling of 111434119243 in words is "one hundred eleven billion, four hundred thirty-four million, one hundred nineteen thousand, two hundred forty-three".
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