Base | Representation |
---|---|
bin | 10000001101110011111… |
… | …011001010111111001011 |
3 | 10221112022100222102212121 |
4 | 100031303323022333023 |
5 | 121224132400433003 |
6 | 2211531003552111 |
7 | 143336263536406 |
oct | 20156373127713 |
9 | 3845270872777 |
10 | 1114341421003 |
11 | 39a653754948 |
12 | 15bb7282b637 |
13 | 8110b0584c5 |
14 | 3bd12056d3d |
15 | 1debea75cbd |
hex | 10373ecafcb |
1114341421003 has 2 divisors, whose sum is σ = 1114341421004. Its totient is φ = 1114341421002.
The previous prime is 1114341420971. The next prime is 1114341421021. The reversal of 1114341421003 is 3001241434111.
It is a strong prime.
It is an emirp because it is prime and its reverse (3001241434111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1114341421003 - 25 = 1114341420971 is a prime.
It is not a weakly prime, because it can be changed into another prime (1114341421033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557170710501 + 557170710502.
It is an arithmetic number, because the mean of its divisors is an integer number (557170710502).
Almost surely, 21114341421003 is an apocalyptic number.
1114341421003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1114341421003 is an equidigital number, since it uses as much as digits as its factorization.
1114341421003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1114341421003 its reverse (3001241434111), we get a palindrome (4115582855114).
The spelling of 1114341421003 in words is "one trillion, one hundred fourteen billion, three hundred forty-one million, four hundred twenty-one thousand, three".
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