Base | Representation |
---|---|
bin | 110011111001000011… |
… | …1110011001101100001 |
3 | 101122122012002021000012 |
4 | 1213302013303031201 |
5 | 3311210144012231 |
6 | 123105414534305 |
7 | 11023332015125 |
oct | 1476207631541 |
9 | 348565067005 |
10 | 111436313441 |
11 | 43294991712 |
12 | 1971b967395 |
13 | a67bc5120b |
14 | 5571c69585 |
15 | 2d73261e2b |
hex | 19f21f3361 |
111436313441 has 2 divisors, whose sum is σ = 111436313442. Its totient is φ = 111436313440.
The previous prime is 111436313399. The next prime is 111436313447. The reversal of 111436313441 is 144313634111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 104600496400 + 6835817041 = 323420^2 + 82679^2 .
It is an emirp because it is prime and its reverse (144313634111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111436313441 - 222 = 111432119137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111436313398 and 111436313407.
It is not a weakly prime, because it can be changed into another prime (111436313447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55718156720 + 55718156721.
It is an arithmetic number, because the mean of its divisors is an integer number (55718156721).
Almost surely, 2111436313441 is an apocalyptic number.
It is an amenable number.
111436313441 is a deficient number, since it is larger than the sum of its proper divisors (1).
111436313441 is an equidigital number, since it uses as much as digits as its factorization.
111436313441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10368, while the sum is 32.
Adding to 111436313441 its reverse (144313634111), we get a palindrome (255749947552).
The spelling of 111436313441 in words is "one hundred eleven billion, four hundred thirty-six million, three hundred thirteen thousand, four hundred forty-one".
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