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111436313441 is a prime number
BaseRepresentation
bin110011111001000011…
…1110011001101100001
3101122122012002021000012
41213302013303031201
53311210144012231
6123105414534305
711023332015125
oct1476207631541
9348565067005
10111436313441
1143294991712
121971b967395
13a67bc5120b
145571c69585
152d73261e2b
hex19f21f3361

111436313441 has 2 divisors, whose sum is σ = 111436313442. Its totient is φ = 111436313440.

The previous prime is 111436313399. The next prime is 111436313447. The reversal of 111436313441 is 144313634111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104600496400 + 6835817041 = 323420^2 + 82679^2 .

It is an emirp because it is prime and its reverse (144313634111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111436313441 - 222 = 111432119137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111436313398 and 111436313407.

It is not a weakly prime, because it can be changed into another prime (111436313447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55718156720 + 55718156721.

It is an arithmetic number, because the mean of its divisors is an integer number (55718156721).

Almost surely, 2111436313441 is an apocalyptic number.

It is an amenable number.

111436313441 is a deficient number, since it is larger than the sum of its proper divisors (1).

111436313441 is an equidigital number, since it uses as much as digits as its factorization.

111436313441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10368, while the sum is 32.

Adding to 111436313441 its reverse (144313634111), we get a palindrome (255749947552).

The spelling of 111436313441 in words is "one hundred eleven billion, four hundred thirty-six million, three hundred thirteen thousand, four hundred forty-one".