11144013132 has 24 divisors (see below), whose sum is σ = 29717368576. Its totient is φ = 3184003728.

The previous prime is 11144013109. The next prime is 11144013137. The reversal of 11144013132 is 23131044111.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a junction number, because it is equal to n+sod(n) for n = 11144013099 and 11144013108.

It is not an unprimeable number, because it can be changed into a prime (11144013137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 66333328 + ... + 66333495.

Almost surely, 2^11144013132 is an apocalyptic number.

11144013132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11144013132 is an abundant number, since it is smaller than the sum of its proper divisors (18573355444).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11144013132 is a wasteful number, since it uses less digits than its factorization.

11144013132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132666837 (or 132666835 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 11144013132 its reverse (23131044111), we get a palindrome (34275057243).

The spelling of 11144013132 in words is "eleven billion, one hundred forty-four million, thirteen thousand, one hundred thirty-two".