11144013130 has 32 divisors (see below), whose sum is σ = 21019046400. Its totient is φ = 4245935232.

The previous prime is 11144013109. The next prime is 11144013137. The reversal of 11144013130 is 3131044111.

It is a super-2 number, since 2×11144013130² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11144013098 and 11144013107.

It is not an unprimeable number, because it can be changed into a prime (11144013137) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46395 + ... + 156334.

It is an arithmetic number, because the mean of its divisors is an integer number (656845200).

Almost surely, 2^11144013130 is an apocalyptic number.

11144013130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11144013130 is a deficient number, since it is larger than the sum of its proper divisors (9875033270).

11144013130 is a wasteful number, since it uses less digits than its factorization.

11144013130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 202998.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11144013130 its reverse (3131044111), we get a palindrome (14275057241).

The spelling of 11144013130 in words is "eleven billion, one hundred forty-four million, thirteen thousand, one hundred thirty".