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1114410413443 is a prime number
BaseRepresentation
bin10000001101111000000…
…010010110110110000011
310221112111011210121201011
4100031320002112312003
5121224303031212233
62211541510421351
7143341062135505
oct20157002266603
93845434717634
101114410413443
1139a689697998
1215bb91961857
138111c433532
143bd1b295d75
151dec5b530cd
hex10378096d83

1114410413443 has 2 divisors, whose sum is σ = 1114410413444. Its totient is φ = 1114410413442.

The previous prime is 1114410413437. The next prime is 1114410413447. The reversal of 1114410413443 is 3443140144111.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1114410413443 is a prime.

It is a super-2 number, since 2×11144104134432 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1114410413447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557205206721 + 557205206722.

It is an arithmetic number, because the mean of its divisors is an integer number (557205206722).

Almost surely, 21114410413443 is an apocalyptic number.

1114410413443 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114410413443 is an equidigital number, since it uses as much as digits as its factorization.

1114410413443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 1114410413443 its reverse (3443140144111), we get a palindrome (4557550557554).

The spelling of 1114410413443 in words is "one trillion, one hundred fourteen billion, four hundred ten million, four hundred thirteen thousand, four hundred forty-three".