Base | Representation |
---|---|
bin | 10000001110011100010… |
… | …111110000011001110011 |
3 | 10221121001122211222021121 |
4 | 100032130113300121303 |
5 | 121232030110043211 |
6 | 2212122204203111 |
7 | 143362143434362 |
oct | 20163427603163 |
9 | 3847048758247 |
10 | 1115020002931 |
11 | 39a9717a555a |
12 | 160121b39497 |
13 | 811b8808b83 |
14 | 3bd782177d9 |
15 | 1e00e417271 |
hex | 1039c5f0673 |
1115020002931 has 2 divisors, whose sum is σ = 1115020002932. Its totient is φ = 1115020002930.
The previous prime is 1115020002883. The next prime is 1115020002953. The reversal of 1115020002931 is 1392000205111.
It is a strong prime.
It is an emirp because it is prime and its reverse (1392000205111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1115020002931 - 223 = 1115011614323 is a prime.
It is a super-2 number, since 2×11150200029312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1115020002896 and 1115020002905.
It is not a weakly prime, because it can be changed into another prime (1115020002991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557510001465 + 557510001466.
It is an arithmetic number, because the mean of its divisors is an integer number (557510001466).
Almost surely, 21115020002931 is an apocalyptic number.
1115020002931 is a deficient number, since it is larger than the sum of its proper divisors (1).
1115020002931 is an equidigital number, since it uses as much as digits as its factorization.
1115020002931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 25.
The spelling of 1115020002931 in words is "one trillion, one hundred fifteen billion, twenty million, two thousand, nine hundred thirty-one".
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