Base | Representation |
---|---|
bin | 1010001001000011101111… |
… | …0101000001100001010001 |
3 | 1110111000000011101222002122 |
4 | 2202100323311001201101 |
5 | 2430143203121343032 |
6 | 35414325000224025 |
7 | 2230420463260625 |
oct | 242207365014121 |
9 | 43430004358078 |
10 | 11150738856017 |
11 | 360a002426572 |
12 | 1301107a6b015 |
13 | 62b682a98807 |
14 | 2a79ad0d7185 |
15 | 1450ca084012 |
hex | a243bd41851 |
11150738856017 has 2 divisors, whose sum is σ = 11150738856018. Its totient is φ = 11150738856016.
The previous prime is 11150738855917. The next prime is 11150738856067. The reversal of 11150738856017 is 71065883705111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8901725747776 + 2249013108241 = 2983576^2 + 1499671^2 .
It is a cyclic number.
It is not a de Polignac number, because 11150738856017 - 210 = 11150738854993 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11150738856017.
It is not a weakly prime, because it can be changed into another prime (11150738856067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5575369428008 + 5575369428009.
It is an arithmetic number, because the mean of its divisors is an integer number (5575369428009).
Almost surely, 211150738856017 is an apocalyptic number.
It is an amenable number.
11150738856017 is a deficient number, since it is larger than the sum of its proper divisors (1).
11150738856017 is an equidigital number, since it uses as much as digits as its factorization.
11150738856017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1411200, while the sum is 53.
The spelling of 11150738856017 in words is "eleven trillion, one hundred fifty billion, seven hundred thirty-eight million, eight hundred fifty-six thousand, seventeen".
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