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11150738856017 is a prime number
BaseRepresentation
bin1010001001000011101111…
…0101000001100001010001
31110111000000011101222002122
42202100323311001201101
52430143203121343032
635414325000224025
72230420463260625
oct242207365014121
943430004358078
1011150738856017
11360a002426572
121301107a6b015
1362b682a98807
142a79ad0d7185
151450ca084012
hexa243bd41851

11150738856017 has 2 divisors, whose sum is σ = 11150738856018. Its totient is φ = 11150738856016.

The previous prime is 11150738855917. The next prime is 11150738856067. The reversal of 11150738856017 is 71065883705111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8901725747776 + 2249013108241 = 2983576^2 + 1499671^2 .

It is a cyclic number.

It is not a de Polignac number, because 11150738856017 - 210 = 11150738854993 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11150738856017.

It is not a weakly prime, because it can be changed into another prime (11150738856067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5575369428008 + 5575369428009.

It is an arithmetic number, because the mean of its divisors is an integer number (5575369428009).

Almost surely, 211150738856017 is an apocalyptic number.

It is an amenable number.

11150738856017 is a deficient number, since it is larger than the sum of its proper divisors (1).

11150738856017 is an equidigital number, since it uses as much as digits as its factorization.

11150738856017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1411200, while the sum is 53.

The spelling of 11150738856017 in words is "eleven trillion, one hundred fifty billion, seven hundred thirty-eight million, eight hundred fifty-six thousand, seventeen".