Base | Representation |
---|---|
bin | 10100110001011110… |
… | …01011111111110011 |
3 | 1001210020021201102122 |
4 | 22120233023333303 |
5 | 140320011110311 |
6 | 5042351304455 |
7 | 543240121133 |
oct | 123057137763 |
9 | 31706251378 |
10 | 11152441331 |
11 | 4803298269 |
12 | 21b2b1b12b |
13 | 108969c815 |
14 | 77b232ac3 |
15 | 4541520db |
hex | 298bcbff3 |
11152441331 has 2 divisors, whose sum is σ = 11152441332. Its totient is φ = 11152441330.
The previous prime is 11152441271. The next prime is 11152441357. The reversal of 11152441331 is 13314425111.
It is an a-pointer prime, because the next prime (11152441357) can be obtained adding 11152441331 to its sum of digits (26).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11152441331 - 230 = 10078699507 is a prime.
It is a super-3 number, since 3×111524413313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 11152441331.
It is not a weakly prime, because it can be changed into another prime (11152441361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5576220665 + 5576220666.
It is an arithmetic number, because the mean of its divisors is an integer number (5576220666).
Almost surely, 211152441331 is an apocalyptic number.
11152441331 is a deficient number, since it is larger than the sum of its proper divisors (1).
11152441331 is an equidigital number, since it uses as much as digits as its factorization.
11152441331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1440, while the sum is 26.
Adding to 11152441331 its reverse (13314425111), we get a palindrome (24466866442).
The spelling of 11152441331 in words is "eleven billion, one hundred fifty-two million, four hundred forty-one thousand, three hundred thirty-one".
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