Base | Representation |
---|---|
bin | 10000001110101101000… |
… | …101001011000011000101 |
3 | 10221121210012100202221100 |
4 | 100032231011023003011 |
5 | 121233113342002010 |
6 | 2212210101010313 |
7 | 143402116335321 |
oct | 20165505130305 |
9 | 3847705322840 |
10 | 1115300344005 |
11 | 39aaa5a719a1 |
12 | 16019b9b3999 |
13 | 81231912873 |
14 | 3bda3550981 |
15 | 1e028d412c0 |
hex | 103ad14b0c5 |
1115300344005 has 96 divisors (see below), whose sum is σ = 1953309496320. Its totient is φ = 588682598400.
The previous prime is 1115300343973. The next prime is 1115300344021. The reversal of 1115300344005 is 5004430035111.
It is a happy number.
1115300344005 is a `hidden beast` number, since 1 + 1 + 15 + 300 + 344 + 0 + 0 + 5 = 666.
It is not a de Polignac number, because 1115300344005 - 25 = 1115300343973 is a prime.
It is a super-4 number, since 4×11153003440054 (a number of 49 digits) contains 4444 as substring.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 1115300344005.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1855740705 + ... + 1855741305.
It is an arithmetic number, because the mean of its divisors is an integer number (20346973920).
Almost surely, 21115300344005 is an apocalyptic number.
1115300344005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1115300344005 is a deficient number, since it is larger than the sum of its proper divisors (838009152315).
1115300344005 is a wasteful number, since it uses less digits than its factorization.
1115300344005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1651 (or 1648 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 1115300344005 its reverse (5004430035111), we get a palindrome (6119730379116).
The spelling of 1115300344005 in words is "one trillion, one hundred fifteen billion, three hundred million, three hundred forty-four thousand, five".
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