Base | Representation |
---|---|
bin | 10000001110101101111… |
… | …110101110011110000111 |
3 | 10221121211020202021211011 |
4 | 100032231332232132013 |
5 | 121233131222300203 |
6 | 2212211400223051 |
7 | 143402361513523 |
oct | 20165576563607 |
9 | 3847736667734 |
10 | 1115315431303 |
11 | 3a0003537237 |
12 | 1601a4a6aa87 |
13 | 81234a95b68 |
14 | 3bda555ad83 |
15 | 1e02a32176d |
hex | 103adfae787 |
1115315431303 has 2 divisors, whose sum is σ = 1115315431304. Its totient is φ = 1115315431302.
The previous prime is 1115315431271. The next prime is 1115315431313. The reversal of 1115315431303 is 3031345135111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1115315431303 - 25 = 1115315431271 is a prime.
It is a super-2 number, since 2×11153154313032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1115315431313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557657715651 + 557657715652.
It is an arithmetic number, because the mean of its divisors is an integer number (557657715652).
Almost surely, 21115315431303 is an apocalyptic number.
1115315431303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1115315431303 is an equidigital number, since it uses as much as digits as its factorization.
1115315431303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8100, while the sum is 31.
The spelling of 1115315431303 in words is "one trillion, one hundred fifteen billion, three hundred fifteen million, four hundred thirty-one thousand, three hundred three".
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