Base | Representation |
---|---|
bin | 10000001110101110010… |
… | …000101010110101101011 |
3 | 10221121211120121021002212 |
4 | 100032232100222311223 |
5 | 121233133423310034 |
6 | 2212212045115335 |
7 | 143402446504136 |
oct | 20165620526553 |
9 | 3847746537085 |
10 | 1115320135019 |
11 | 3a000615a202 |
12 | 1601a6558b4b |
13 | 81235a51b1c |
14 | 3bda602321d |
15 | 1e02a9502ce |
hex | 103ae42ad6b |
1115320135019 has 2 divisors, whose sum is σ = 1115320135020. Its totient is φ = 1115320135018.
The previous prime is 1115320134991. The next prime is 1115320135031. The reversal of 1115320135019 is 9105310235111.
It is a strong prime.
It is an emirp because it is prime and its reverse (9105310235111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1115320135019 - 228 = 1115051699563 is a prime.
It is a super-2 number, since 2×11153201350192 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1115320135099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557660067509 + 557660067510.
It is an arithmetic number, because the mean of its divisors is an integer number (557660067510).
Almost surely, 21115320135019 is an apocalyptic number.
1115320135019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1115320135019 is an equidigital number, since it uses as much as digits as its factorization.
1115320135019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4050, while the sum is 32.
The spelling of 1115320135019 in words is "one trillion, one hundred fifteen billion, three hundred twenty million, one hundred thirty-five thousand, nineteen".
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