Base | Representation |
---|---|
bin | 10100110011011000… |
… | …10001011111100111 |
3 | 1001211100102021112211 |
4 | 22121230101133213 |
5 | 140333111022011 |
6 | 5044122424251 |
7 | 543523204135 |
oct | 123154213747 |
9 | 31740367484 |
10 | 11168454631 |
11 | 48113352a4 |
12 | 21b8362087 |
13 | 108cab8449 |
14 | 77d400755 |
15 | 455766b21 |
hex | 299b117e7 |
11168454631 has 2 divisors, whose sum is σ = 11168454632. Its totient is φ = 11168454630.
The previous prime is 11168454529. The next prime is 11168454677. The reversal of 11168454631 is 13645486111.
It is a strong prime.
It is an emirp because it is prime and its reverse (13645486111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11168454631 - 27 = 11168454503 is a prime.
It is a super-2 number, since 2×111684546312 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11168454331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5584227315 + 5584227316.
It is an arithmetic number, because the mean of its divisors is an integer number (5584227316).
Almost surely, 211168454631 is an apocalyptic number.
11168454631 is a deficient number, since it is larger than the sum of its proper divisors (1).
11168454631 is an equidigital number, since it uses as much as digits as its factorization.
11168454631 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 69120, while the sum is 40.
The spelling of 11168454631 in words is "eleven billion, one hundred sixty-eight million, four hundred fifty-four thousand, six hundred thirty-one".
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