Base | Representation |
---|---|
bin | 10100110011110111… |
… | …00110100011011011 |
3 | 1001211121222102210012 |
4 | 22121323212203123 |
5 | 140340123114201 |
6 | 5044344512135 |
7 | 543602311505 |
oct | 123173464333 |
9 | 31747872705 |
10 | 11172473051 |
11 | 481362a403 |
12 | 21b977b64b |
13 | 10908944cc |
14 | 77db68d75 |
15 | 455cac5bb |
hex | 299ee68db |
11172473051 has 2 divisors, whose sum is σ = 11172473052. Its totient is φ = 11172473050.
The previous prime is 11172473021. The next prime is 11172473057. The reversal of 11172473051 is 15037427111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11172473051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11172472999 and 11172473017.
It is not a weakly prime, because it can be changed into another prime (11172473057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5586236525 + 5586236526.
It is an arithmetic number, because the mean of its divisors is an integer number (5586236526).
Almost surely, 211172473051 is an apocalyptic number.
11172473051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11172473051 is an equidigital number, since it uses as much as digits as its factorization.
11172473051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5880, while the sum is 32.
The spelling of 11172473051 in words is "eleven billion, one hundred seventy-two million, four hundred seventy-three thousand, fifty-one".
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