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111796548313 is a prime number
BaseRepresentation
bin110100000011110010…
…1111111001011011001
3101200120021221002100111
41220013211333023121
53312424404021223
6123205244004321
711035264660432
oct1500745771331
9350507832314
10111796548313
114345a26748a
12198005306a1
13a70877bb48
1455a7a3c489
152d94bbd30d
hex1a0797f2d9

111796548313 has 2 divisors, whose sum is σ = 111796548314. Its totient is φ = 111796548312.

The previous prime is 111796548287. The next prime is 111796548323. The reversal of 111796548313 is 313845697111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68187832384 + 43608715929 = 261128^2 + 208827^2 .

It is an emirp because it is prime and its reverse (313845697111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111796548313 is a prime.

It is not a weakly prime, because it can be changed into another prime (111796548323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55898274156 + 55898274157.

It is an arithmetic number, because the mean of its divisors is an integer number (55898274157).

Almost surely, 2111796548313 is an apocalyptic number.

It is an amenable number.

111796548313 is a deficient number, since it is larger than the sum of its proper divisors (1).

111796548313 is an equidigital number, since it uses as much as digits as its factorization.

111796548313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 544320, while the sum is 49.

The spelling of 111796548313 in words is "one hundred eleven billion, seven hundred ninety-six million, five hundred forty-eight thousand, three hundred thirteen".