Base | Representation |
---|---|
bin | 110100000011110010… |
… | …1111111001011011001 |
3 | 101200120021221002100111 |
4 | 1220013211333023121 |
5 | 3312424404021223 |
6 | 123205244004321 |
7 | 11035264660432 |
oct | 1500745771331 |
9 | 350507832314 |
10 | 111796548313 |
11 | 4345a26748a |
12 | 198005306a1 |
13 | a70877bb48 |
14 | 55a7a3c489 |
15 | 2d94bbd30d |
hex | 1a0797f2d9 |
111796548313 has 2 divisors, whose sum is σ = 111796548314. Its totient is φ = 111796548312.
The previous prime is 111796548287. The next prime is 111796548323. The reversal of 111796548313 is 313845697111.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 68187832384 + 43608715929 = 261128^2 + 208827^2 .
It is an emirp because it is prime and its reverse (313845697111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111796548313 is a prime.
It is not a weakly prime, because it can be changed into another prime (111796548323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55898274156 + 55898274157.
It is an arithmetic number, because the mean of its divisors is an integer number (55898274157).
Almost surely, 2111796548313 is an apocalyptic number.
It is an amenable number.
111796548313 is a deficient number, since it is larger than the sum of its proper divisors (1).
111796548313 is an equidigital number, since it uses as much as digits as its factorization.
111796548313 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 544320, while the sum is 49.
The spelling of 111796548313 in words is "one hundred eleven billion, seven hundred ninety-six million, five hundred forty-eight thousand, three hundred thirteen".
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