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11182798066703 is a prime number
BaseRepresentation
bin1010001010111011001010…
…1101001101010000001111
31110121001202102110121111012
42202232302231031100033
52431204332301113303
635441150112315435
72232634106130314
oct242566255152017
943531672417435
1011182798066703
113621663a7900a
121307374542b7b
136316c1969873
142a9370c10d0b
15145d548695d8
hexa2bb2b4d40f

11182798066703 has 2 divisors, whose sum is σ = 11182798066704. Its totient is φ = 11182798066702.

The previous prime is 11182798066667. The next prime is 11182798066723. The reversal of 11182798066703 is 30766089728111.

11182798066703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11182798066703 - 210 = 11182798065679 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11182798066723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5591399033351 + 5591399033352.

It is an arithmetic number, because the mean of its divisors is an integer number (5591399033352).

Almost surely, 211182798066703 is an apocalyptic number.

11182798066703 is a deficient number, since it is larger than the sum of its proper divisors (1).

11182798066703 is an equidigital number, since it uses as much as digits as its factorization.

11182798066703 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6096384, while the sum is 59.

The spelling of 11182798066703 in words is "eleven trillion, one hundred eighty-two billion, seven hundred ninety-eight million, sixty-six thousand, seven hundred three".