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112000110011893 is a prime number
BaseRepresentation
bin11001011101110100001110…
…110001011010010111110101
3112200120002212020101211000201
4121131310032301122113311
5104140002211130340033
61034112050142440501
732406512064226165
oct3135641661322765
9480502766354021
10112000110011893
1132760a862a05a4
121068a456293131
134a6574657340c
141d92b9726a5a5
15ce35a71c147d
hex65dd0ec5a5f5

112000110011893 has 2 divisors, whose sum is σ = 112000110011894. Its totient is φ = 112000110011892.

The previous prime is 112000110011873. The next prime is 112000110012041. The reversal of 112000110011893 is 398110011000211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 72495654455844 + 39504455556049 = 8514438^2 + 6285257^2 .

It is a cyclic number.

It is not a de Polignac number, because 112000110011893 - 241 = 109801086756341 is a prime.

It is a super-2 number, since 2×1120001100118932 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112000110011813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56000055005946 + 56000055005947.

It is an arithmetic number, because the mean of its divisors is an integer number (56000055005947).

Almost surely, 2112000110011893 is an apocalyptic number.

It is an amenable number.

112000110011893 is a deficient number, since it is larger than the sum of its proper divisors (1).

112000110011893 is an equidigital number, since it uses as much as digits as its factorization.

112000110011893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 28.

The spelling of 112000110011893 in words is "one hundred twelve trillion, one hundred ten million, eleven thousand, eight hundred ninety-three".