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112001121212102 = 256000560606051
BaseRepresentation
bin11001011101110101001011…
…000010110101011011000110
3112200120012110201011002221022
4121131311023002311123012
5104140011244012241402
61034112334344151142
732406546123255563
oct3135651302653306
9480505421132838
10112001121212102
1132761455074251
121068a698a684b2
134a65877c02535
141d92c5169186a
15ce3615d662a2
hex65dd4b0b56c6

112001121212102 has 4 divisors (see below), whose sum is σ = 168001681818156. Its totient is φ = 56000560606050.

The previous prime is 112001121212081. The next prime is 112001121212137. The reversal of 112001121212102 is 201212121100211.

112001121212102 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28000280303024 + ... + 28000280303027.

It is an arithmetic number, because the mean of its divisors is an integer number (42000420454539).

Almost surely, 2112001121212102 is an apocalyptic number.

112001121212102 is a deficient number, since it is larger than the sum of its proper divisors (56000560606054).

112001121212102 is an equidigital number, since it uses as much as digits as its factorization.

112001121212102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56000560606053.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 112001121212102 its reverse (201212121100211), we get a palindrome (313213242312313).

The spelling of 112001121212102 in words is "one hundred twelve trillion, one billion, one hundred twenty-one million, two hundred twelve thousand, one hundred two".

Divisors: 1 2 56000560606051 112001121212102