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11200212113 is a prime number
BaseRepresentation
bin10100110111001010…
…11010110010010001
31001220120011201121212
422123211122302101
5140414223241423
65051215225505
7544360142426
oct123345326221
931816151555
1011200212113
114828256152
122206b18295
13109655735c
14783709d4d
1545843b578
hex29b95ac91

11200212113 has 2 divisors, whose sum is σ = 11200212114. Its totient is φ = 11200212112.

The previous prime is 11200212103. The next prime is 11200212151. The reversal of 11200212113 is 31121200211.

11200212113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11079036049 + 121176064 = 105257^2 + 11008^2 .

It is a cyclic number.

It is not a de Polignac number, because 11200212113 - 24 = 11200212097 is a prime.

It is not a weakly prime, because it can be changed into another prime (11200212103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600106056 + 5600106057.

It is an arithmetic number, because the mean of its divisors is an integer number (5600106057).

Almost surely, 211200212113 is an apocalyptic number.

It is an amenable number.

11200212113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11200212113 is an equidigital number, since it uses as much as digits as its factorization.

11200212113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 11200212113 its reverse (31121200211), we get a palindrome (42321412324).

The spelling of 11200212113 in words is "eleven billion, two hundred million, two hundred twelve thousand, one hundred thirteen".