Base | Representation |
---|---|
bin | 11001011101110110010111… |
… | …100000101011010100011011 |
3 | 112200120022210010010202000201 |
4 | 121131312113200223110123 |
5 | 104140021410422302301 |
6 | 1034113105533043031 |
7 | 32406622661541601 |
oct | 3135662740532433 |
9 | 480508703122021 |
10 | 112002404103451 |
11 | 32761a53246534 |
12 | 1068a996626477 |
13 | 4a65a2092a144 |
14 | 1d92d33bdb871 |
15 | ce368d7c7201 |
hex | 65dd9782b51b |
112002404103451 has 2 divisors, whose sum is σ = 112002404103452. Its totient is φ = 112002404103450.
The previous prime is 112002404103437. The next prime is 112002404103481. The reversal of 112002404103451 is 154301404200211.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112002404103451 - 243 = 103206311081243 is a prime.
It is a super-2 number, since 2×1120024041034512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112002404103431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56001202051725 + 56001202051726.
It is an arithmetic number, because the mean of its divisors is an integer number (56001202051726).
Almost surely, 2112002404103451 is an apocalyptic number.
112002404103451 is a deficient number, since it is larger than the sum of its proper divisors (1).
112002404103451 is an equidigital number, since it uses as much as digits as its factorization.
112002404103451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 28.
Adding to 112002404103451 its reverse (154301404200211), we get a palindrome (266303808303662).
The spelling of 112002404103451 in words is "one hundred twelve trillion, two billion, four hundred four million, one hundred three thousand, four hundred fifty-one".
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