Base | Representation |
---|---|
bin | 10100110111001100… |
… | …01001111011011011 |
3 | 1001220120112112111122 |
4 | 22123212021323123 |
5 | 140414300431321 |
6 | 5051223315455 |
7 | 544361605412 |
oct | 123346117333 |
9 | 31816475448 |
10 | 11200405211 |
11 | 4828378236 |
12 | 2206babb8b |
13 | 10965c4208 |
14 | 78375a479 |
15 | 4584788ab |
hex | 29b989edb |
11200405211 has 2 divisors, whose sum is σ = 11200405212. Its totient is φ = 11200405210.
The previous prime is 11200405193. The next prime is 11200405213. The reversal of 11200405211 is 11250400211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11200405211 is a prime.
Together with 11200405213, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11200405211.
It is not a weakly prime, because it can be changed into another prime (11200405213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600202605 + 5600202606.
It is an arithmetic number, because the mean of its divisors is an integer number (5600202606).
Almost surely, 211200405211 is an apocalyptic number.
11200405211 is a deficient number, since it is larger than the sum of its proper divisors (1).
11200405211 is an equidigital number, since it uses as much as digits as its factorization.
11200405211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 11200405211 its reverse (11250400211), we get a palindrome (22450805422).
Subtracting 11200405211 from its reverse (11250400211), we obtain a triangular number (49995000 = T9999).
The spelling of 11200405211 in words is "eleven billion, two hundred million, four hundred five thousand, two hundred eleven".
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