112011102000253 has 2 divisors, whose sum is σ = 112011102000254. Its totient is φ = 112011102000252.

The previous prime is 112011102000209. The next prime is 112011102000289. The reversal of 112011102000253 is 352000201110211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111594145098969 + 416956901284 = 10563813^2 + 645722^2 .

It is an emirp because it is prime and its reverse (352000201110211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112011102000253 - 2¹³ = 112011101992061 is a prime.

It is a super-2 number, since 2×112011102000253² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 112011102000253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112011102000353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56005551000126 + 56005551000127.

It is an arithmetic number, because the mean of its divisors is an integer number (56005551000127).

Almost surely, 2^{112011102000253} is an apocalyptic number.

It is an amenable number.

112011102000253 is a deficient number, since it is larger than the sum of its proper divisors (1).

112011102000253 is an equidigital number, since it uses as much as digits as its factorization.

112011102000253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 112011102000253 its reverse (352000201110211), we get a palindrome (464011303110464).

The spelling of 112011102000253 in words is "one hundred twelve trillion, eleven billion, one hundred two million, two hundred fifty-three", and thus it is an aban number.