Base | Representation |
---|---|
bin | 11001011101111110011111… |
… | …001000110110100000010011 |
3 | 112200121011021200102021202022 |
4 | 121131332133020312200103 |
5 | 104140142234213311011 |
6 | 1034121111000042055 |
7 | 32410352010533261 |
oct | 3135763710664023 |
9 | 480534250367668 |
10 | 112011122010131 |
11 | 32765717283893 |
12 | 1069060a16332b |
13 | 4a667acb0bcc6 |
14 | 1d9351d981431 |
15 | ce39edd308db |
hex | 65df9f236813 |
112011122010131 has 2 divisors, whose sum is σ = 112011122010132. Its totient is φ = 112011122010130.
The previous prime is 112011122010043. The next prime is 112011122010143. The reversal of 112011122010131 is 131010221110211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112011122010131 is a prime.
It is a super-2 number, since 2×1120111220101312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112011122010331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56005561005065 + 56005561005066.
It is an arithmetic number, because the mean of its divisors is an integer number (56005561005066).
Almost surely, 2112011122010131 is an apocalyptic number.
112011122010131 is a deficient number, since it is larger than the sum of its proper divisors (1).
112011122010131 is an equidigital number, since it uses as much as digits as its factorization.
112011122010131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 112011122010131 its reverse (131010221110211), we get a palindrome (243021343120342).
The spelling of 112011122010131 in words is "one hundred twelve trillion, eleven billion, one hundred twenty-two million, ten thousand, one hundred thirty-one".
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