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11201121131 is a prime number
BaseRepresentation
bin10100110111010001…
…11000101101101011
31001220121212220120012
422123220320231223
5140414441334011
65051250522135
7544400646554
oct123350705553
931817786505
1011201121131
114828817102
12220729634b
1310967b5035
147838a532b
1545856aa8b
hex29ba38b6b

11201121131 has 2 divisors, whose sum is σ = 11201121132. Its totient is φ = 11201121130.

The previous prime is 11201121119. The next prime is 11201121133. The reversal of 11201121131 is 13112110211.

It is a strong prime.

It is an emirp because it is prime and its reverse (13112110211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11201121131 - 26 = 11201121067 is a prime.

It is a super-2 number, since 2×112011211312 (a number of 21 digits) contains 22 as substring.

Together with 11201121133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11201121133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600560565 + 5600560566.

It is an arithmetic number, because the mean of its divisors is an integer number (5600560566).

Almost surely, 211201121131 is an apocalyptic number.

11201121131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11201121131 is an equidigital number, since it uses as much as digits as its factorization.

11201121131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 11201121131 its reverse (13112110211), we get a palindrome (24313231342).

The spelling of 11201121131 in words is "eleven billion, two hundred one million, one hundred twenty-one thousand, one hundred thirty-one".