Base | Representation |
---|---|
bin | 10000010011001100010… |
… | …110101100111000000111 |
3 | 10222002020002101200001012 |
4 | 100103030112230320013 |
5 | 121323001210000012 |
6 | 2214324230552435 |
7 | 143632421622461 |
oct | 20231426547007 |
9 | 3862202350035 |
10 | 1120120000007 |
11 | 3a20495a1878 |
12 | 161105b0871b |
13 | 8181c2a9b18 |
14 | 3c2dd6a9131 |
15 | 1e20c022622 |
hex | 104cc5ace07 |
1120120000007 has 2 divisors, whose sum is σ = 1120120000008. Its totient is φ = 1120120000006.
The previous prime is 1120119999991. The next prime is 1120120000063. The reversal of 1120120000007 is 7000000210211.
It is a weak prime.
It is an emirp because it is prime and its reverse (7000000210211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1120120000007 - 24 = 1120119999991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1120119999946 and 1120120000000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1120120000907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560060000003 + 560060000004.
It is an arithmetic number, because the mean of its divisors is an integer number (560060000004).
Almost surely, 21120120000007 is an apocalyptic number.
1120120000007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120120000007 is an equidigital number, since it uses as much as digits as its factorization.
1120120000007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 14.
Adding to 1120120000007 its reverse (7000000210211), we get a palindrome (8120120210218).
The spelling of 1120120000007 in words is "one trillion, one hundred twenty billion, one hundred twenty million, seven", and thus it is an aban number.
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