1120120001113 has 2 divisors, whose sum is σ = 1120120001114. Its totient is φ = 1120120001112.

The previous prime is 1120120001083. The next prime is 1120120001137. The reversal of 1120120001113 is 3111000210211.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 854825986624 + 265294014489 = 924568^2 + 515067^2 .

It is a cyclic number.

It is not a de Polignac number, because 1120120001113 - 2⁵ = 1120120001081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1120120001093 and 1120120001102.

It is not a weakly prime, because it can be changed into another prime (1120120001213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560060000556 + 560060000557.

It is an arithmetic number, because the mean of its divisors is an integer number (560060000557).

Almost surely, 2^{1120120001113} is an apocalyptic number.

It is an amenable number.

1120120001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1120120001113 is an equidigital number, since it uses as much as digits as its factorization.

1120120001113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1120120001113 its reverse (3111000210211), we get a palindrome (4231120211324).

The spelling of 1120120001113 in words is "one trillion, one hundred twenty billion, one hundred twenty million, one thousand, one hundred thirteen".