Base | Representation |
---|---|
bin | 10000010011001100010… |
… | …110110010000010001101 |
3 | 10222002020002102202000122 |
4 | 100103030112302002031 |
5 | 121323001211134013 |
6 | 2214324231234325 |
7 | 143632422041201 |
oct | 20231426620215 |
9 | 3862202382018 |
10 | 1120120021133 |
11 | 3a2049606733 |
12 | 161105b189a5 |
13 | 8181c2b6619 |
14 | 3c2dd6b2b01 |
15 | 1e20c028a08 |
hex | 104cc5b208d |
1120120021133 has 2 divisors, whose sum is σ = 1120120021134. Its totient is φ = 1120120021132.
The previous prime is 1120120021093. The next prime is 1120120021177. The reversal of 1120120021133 is 3311200210211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 706519259209 + 413600761924 = 840547^2 + 643118^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1120120021133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1120120021183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560060010566 + 560060010567.
It is an arithmetic number, because the mean of its divisors is an integer number (560060010567).
Almost surely, 21120120021133 is an apocalyptic number.
It is an amenable number.
1120120021133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120120021133 is an equidigital number, since it uses as much as digits as its factorization.
1120120021133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1120120021133 its reverse (3311200210211), we get a palindrome (4431320231344).
The spelling of 1120120021133 in words is "one trillion, one hundred twenty billion, one hundred twenty million, twenty-one thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.860 sec. • engine limits •