Base | Representation |
---|---|
bin | 110100001010001110… |
… | …0010000001110110101 |
3 | 101201010022112021102001 |
4 | 1220110130100032311 |
5 | 3313400044204113 |
6 | 123242504015301 |
7 | 11043523100524 |
oct | 1502434201665 |
9 | 351108467361 |
10 | 112012100533 |
11 | 4355aa02013 |
12 | 19860761531 |
13 | a74131cc38 |
14 | 55c850c4bb |
15 | 2da8a9a7dd |
hex | 1a147103b5 |
112012100533 has 2 divisors, whose sum is σ = 112012100534. Its totient is φ = 112012100532.
The previous prime is 112012100489. The next prime is 112012100537. The reversal of 112012100533 is 335001210211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 72545112964 + 39466987569 = 269342^2 + 198663^2 .
It is a cyclic number.
It is not a de Polignac number, because 112012100533 - 29 = 112012100021 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 112012100533.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112012100537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006050266 + 56006050267.
It is an arithmetic number, because the mean of its divisors is an integer number (56006050267).
Almost surely, 2112012100533 is an apocalyptic number.
It is an amenable number.
112012100533 is a deficient number, since it is larger than the sum of its proper divisors (1).
112012100533 is an equidigital number, since it uses as much as digits as its factorization.
112012100533 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180, while the sum is 19.
Adding to 112012100533 its reverse (335001210211), we get a palindrome (447013310744).
The spelling of 112012100533 in words is "one hundred twelve billion, twelve million, one hundred thousand, five hundred thirty-three".
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