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11201213533 is a prime number
BaseRepresentation
bin10100110111010010…
…01111010001011101
31001220122001121022111
422123221033101131
5140420002313113
65051252514021
7544401513136
oct123351172135
931818047274
1011201213533
11482887a574
12220731b911
131096818103
147838cac8d
1545858813d
hex29ba4f45d

11201213533 has 2 divisors, whose sum is σ = 11201213534. Its totient is φ = 11201213532.

The previous prime is 11201213519. The next prime is 11201213549. The reversal of 11201213533 is 33531210211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8963734329 + 2237479204 = 94677^2 + 47302^2 .

It is an emirp because it is prime and its reverse (33531210211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11201213533 - 25 = 11201213501 is a prime.

It is a super-2 number, since 2×112012135332 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11201211533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600606766 + 5600606767.

It is an arithmetic number, because the mean of its divisors is an integer number (5600606767).

Almost surely, 211201213533 is an apocalyptic number.

It is an amenable number.

11201213533 is a deficient number, since it is larger than the sum of its proper divisors (1).

11201213533 is an equidigital number, since it uses as much as digits as its factorization.

11201213533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 11201213533 its reverse (33531210211), we get a palindrome (44732423744).

The spelling of 11201213533 in words is "eleven billion, two hundred one million, two hundred thirteen thousand, five hundred thirty-three".