Base | Representation |
---|---|
bin | 11001011101111111100000… |
… | …100110001010001100111011 |
3 | 112200121021010012212201112121 |
4 | 121131333200212022030323 |
5 | 104140202011333241102 |
6 | 1034121411550222111 |
7 | 32410421144230132 |
oct | 3135774046121473 |
9 | 480537105781477 |
10 | 112012220212027 |
11 | 32766130180163 |
12 | 10690875ab4937 |
13 | 4a669264b0405 |
14 | 1d935c5772919 |
15 | ce3a6545db37 |
hex | 65dfe098a33b |
112012220212027 has 2 divisors, whose sum is σ = 112012220212028. Its totient is φ = 112012220212026.
The previous prime is 112012220212007. The next prime is 112012220212063. The reversal of 112012220212027 is 720212022210211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112012220212027 - 239 = 111462464398139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112012220211992 and 112012220212010.
It is not a weakly prime, because it can be changed into another prime (112012220212007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006110106013 + 56006110106014.
It is an arithmetic number, because the mean of its divisors is an integer number (56006110106014).
Almost surely, 2112012220212027 is an apocalyptic number.
112012220212027 is a deficient number, since it is larger than the sum of its proper divisors (1).
112012220212027 is an equidigital number, since it uses as much as digits as its factorization.
112012220212027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 112012220212027 its reverse (720212022210211), we get a palindrome (832224242422238).
The spelling of 112012220212027 in words is "one hundred twelve trillion, twelve billion, two hundred twenty million, two hundred twelve thousand, twenty-seven".
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