Base | Representation |
---|---|
bin | 11001011101111111100110… |
… | …001000010010000111001101 |
3 | 112200121021100200120001020210 |
4 | 121131333212020102013031 |
5 | 104140202204114342110 |
6 | 1034121425104033033 |
7 | 32410423352254425 |
oct | 3135774610220715 |
9 | 480537320501223 |
10 | 112012313043405 |
11 | 32766178615805 |
12 | 106908a1002779 |
13 | 4a6693c7b4018 |
14 | 1d935d3c19485 |
15 | ce3a6d699520 |
hex | 65dfe62121cd |
112012313043405 has 32 divisors (see below), whose sum is σ = 189513200636928. Its totient is φ = 56402738265600.
The previous prime is 112012313043359. The next prime is 112012313043419. The reversal of 112012313043405 is 504340313210211.
It is not a de Polignac number, because 112012313043405 - 26 = 112012313043341 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2937623554 + ... + 2937661683.
It is an arithmetic number, because the mean of its divisors is an integer number (5922287519904).
Almost surely, 2112012313043405 is an apocalyptic number.
112012313043405 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
112012313043405 is a deficient number, since it is larger than the sum of its proper divisors (77500887593523).
112012313043405 is a wasteful number, since it uses less digits than its factorization.
112012313043405 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5875285317.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 112012313043405 its reverse (504340313210211), we get a palindrome (616352626253616).
The spelling of 112012313043405 in words is "one hundred twelve trillion, twelve billion, three hundred thirteen million, forty-three thousand, four hundred five".
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