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112012343 is a prime number
BaseRepresentation
bin1101010110100…
…10110000110111
321210202211001022
412223102300313
5212133343333
615040451355
72530042412
oct653226067
9253684038
10112012343
1158256593
1231619b5b
131a28b2c1
1410c3ab79
159c78c98
hex6ad2c37

112012343 has 2 divisors, whose sum is σ = 112012344. Its totient is φ = 112012342.

The previous prime is 112012339. The next prime is 112012361. The reversal of 112012343 is 343210211.

It is a weak prime.

It is an emirp because it is prime and its reverse (343210211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112012343 - 22 = 112012339 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114012343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006171 + 56006172.

It is an arithmetic number, because the mean of its divisors is an integer number (56006172).

Almost surely, 2112012343 is an apocalyptic number.

112012343 is a deficient number, since it is larger than the sum of its proper divisors (1).

112012343 is an equidigital number, since it uses as much as digits as its factorization.

112012343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 112012343 is about 10583.5883801289. The cubic root of 112012343 is about 482.0461595572.

Adding to 112012343 its reverse (343210211), we get a palindrome (455222554).

The spelling of 112012343 in words is "one hundred twelve million, twelve thousand, three hundred forty-three".