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112013047 is a prime number
BaseRepresentation
bin1101010110100…
…10111011110111
321210202212000101
412223102323313
5212133404142
615040454531
72530044436
oct653227367
9253685011
10112013047
1158257073
123161a447
131a28b713
1410c3b11d
159c790b7
hex6ad2ef7

112013047 has 2 divisors, whose sum is σ = 112013048. Its totient is φ = 112013046.

The previous prime is 112013039. The next prime is 112013081. The reversal of 112013047 is 740310211.

It is a weak prime.

It is an emirp because it is prime and its reverse (740310211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112013047 - 23 = 112013039 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112017047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006523 + 56006524.

It is an arithmetic number, because the mean of its divisors is an integer number (56006524).

Almost surely, 2112013047 is an apocalyptic number.

112013047 is a deficient number, since it is larger than the sum of its proper divisors (1).

112013047 is an equidigital number, since it uses as much as digits as its factorization.

112013047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 19.

The square root of 112013047 is about 10583.6216391177. The cubic root of 112013047 is about 482.0471694453.

Subtracting from 112013047 its sum of digits (19), we obtain a triangular number (112013028 = T14967).

Adding to 112013047 its reverse (740310211), we get a palindrome (852323258).

The spelling of 112013047 in words is "one hundred twelve million, thirteen thousand, forty-seven".